Sponsor Area

Integrals

Question
CBSEENMA12036132

The distance of the point (1, 3, –7) from the plane passing through the point (1, –1, –1), having normal perpendicular to both the linesfraction numerator straight x minus 1 over denominator 1 end fraction space equals space fraction numerator straight y plus 2 over denominator negative 2 end fraction space equals space fraction numerator straight z minus 4 over denominator 3 end fraction space and space fraction numerator straight x minus 2 over denominator 2 end fraction space equals space fraction numerator straight y plus 1 over denominator negative 1 end fraction space equals space fraction numerator straight z plus 7 over denominator negative 1 end fraction is

  • fraction numerator 10 over denominator square root of 74 end fraction
  • fraction numerator 20 over denominator square root of 74 end fraction
  • fraction numerator 10 over denominator square root of 83 end fraction
  • fraction numerator 5 over denominator square root of 83 end fraction

Solution

C.

fraction numerator 10 over denominator square root of 83 end fraction

Normal vector
open vertical bar table row cell straight i with hat on top end cell cell straight j with hat on top end cell cell straight k with hat on top end cell row 1 cell negative 2 end cell 3 row 2 cell negative 1 end cell cell negative 1 end cell end table close vertical bar space equals space 5 straight i with hat on top space plus space 7 straight j with hat on top space plus 3 straight k with hat on top
So space plane space is space
5 left parenthesis straight x minus 1 right parenthesis space plus space 7 left parenthesis straight y plus 1 right parenthesis space plus space 3 left parenthesis straight z plus 1 right parenthesis space equals space 0 space
rightwards double arrow space 5 space straight x space plus 7 straight y space plus space 3 straight z space plus space 5 space equals space 0
Distance space fraction numerator 5 plus 21 minus 21 plus 5 over denominator square root of 25 plus 49 plus 9 end root end fraction space equals space fraction numerator 10 over denominator square root of 83 end fraction

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