+91-8076753736 [email protected]

-->

Matrices

Question

Wired Faculty App

Let f : R → R be defined by
$straight f left parenthesis straight x right parenthesis space equals space open curly brackets table attributes columnalign left end attributes row cell straight k minus 2 straight x comma if space straight x space less or equal than space minus 1 end cell row cell 2 straight x space plus 3 comma space if space straight x greater than negative 1 end cell end table close$
If f has a local minimum at x = - 1 then a possible value of k is

1

0

-1/2

-1

Solution

C.

-1/2

k – 2x > 1 k + 2 = 1
k > 1 + 2x k = -1
k > 1 + 2(-1)
k > -1

Some More Questions From Matrices Chapter

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation