An urn contains nine balls of which three are red, four are blue and two are green. Three balls are drawn at random without replacement from the urn. The probability that the three balls have different colours is

1/3

2/7

1/21

2/23

Solution

2/7

Number of ways to select exactly one ball

=³C₁ × ⁴C₁ × ²C₁
Number of ways to select 3 balls out of 9 is
⁹C₃
Required probability $fraction numerator 3 space straight x space 4 space straight x space 2 over denominator left parenthesis to the power of 9 straight C subscript 3 right parenthesis end fraction space equals space 2 over 7$

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Integrals

An urn contains nine balls of which three are red, four are blue and two are green. Three balls are drawn at random without replacement from the urn. The probability that the three balls have different colours is

1/3

2/7

1/21

2/23

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Integrals

An urn contains nine balls of which three are red, four are blue and two are green. Three balls are drawn at random without replacement from the urn. The probability that the three balls have different colours is 1/3 2/7 1/21 2/23

Some More Questions From Integrals Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

An urn contains nine balls of which three are red, four are blue and two are green. Three balls are drawn at random without replacement from the urn. The probability that the three balls have different colours is

1/3

2/7

1/21

2/23