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Three Dimensional Geometry

Question

Let A(h, k), B(1, 1) and C(2, 1) be the vertices of a right-angled triangle with AC as its hypotenuse. If the area of the triangle is 1, then the set of values which ‘k’ can take is given by

{1, 3}

{0, 2}

{–1, 3}

{−3, −2}

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Solution

{–1, 3}

1 half space straight x space 1 space left parenthesis straight k minus 1 right parenthesis space equals space plus-or-minus 1 straight k minus 1 space equals space plus-or-minus 2 straight k space equals 3 straight k equals negative 1