The non−zero verctors $straight a with rightwards arrow on top comma space straight b with rightwards arrow on top space and space straight c with rightwards arrow on top$ are related by $straight a with rightwards arrow on top space equals space 8 straight b with rightwards arrow on top space and space straight c with rightwards arrow on top space equals space minus space 7 straight b with rightwards arrow on top$ .Then the angle between $straight a with rightwards arrow on top space and space straight c with rightwards arrow on top$ is

0

π/4

π/2

π

Solution

Since space straight a with rightwards arrow on top space equals space 8 straight b with rightwards arrow on top straight c with rightwards arrow on top space equals space minus 7 straight b with rightwards arrow on top therefore space straight a with rightwards arrow on top space and space straight b with rightwards arrow on top space are space like space vectors space and space straight b with rightwards arrow on top space and space straight c with rightwards arrow on top space are space unlike. rightwards double arrow straight a with rightwards arrow on top space and space straight c with rightwards arrow on top space will space be space unlike

Some More Questions From Vector Algebra Chapter

For Daily Free Study Material Join wiredfaculty