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Vector Algebra

Question
CBSEENMA12036066

The intercepts on X- axis made by tangents to the curve, straight y space equals space integral subscript 0 superscript straight x vertical line straight t vertical line space dt comma space straight x space straight epsilon space straight R which are parallel to the line y =2x, are equal to

  • ±1

  • ±2

  • ±3

  • ±4

Solution

A.

±1

integral subscript 0 superscript straight x space vertical line straight t vertical line space dt comma space parallel space to space straight y space equals space 2 straight x
therefore space dy over dx space equals space vertical line straight x vertical line space equals space 2
straight x space equals space plus-or-minus 2
therefore space Points comma space straight y space equals space integral subscript 0 superscript plus-or-minus 2 end superscript vertical line straight t vertical line space dt space equals space plus-or-minus 2
∴ Equation of tangent is
y-2 = 2(x-2)
and y +2 = 2 (x+2)
for x - intercept, put y = 0, we get
 0- 2 = 2(x-2)
and 0+2 = 2(x+2)
x = ±1

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