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Matrices

Question
CBSEENMA12036065

If P = open square brackets table row 1 straight alpha 3 row 1 3 3 row 2 4 4 end table close square brackets is the adjoint of a 3 x3 matrix A and |A| = 4, then α is equal to 

  • 4

  • 11

  • 5

  • 0

Solution

B.

11

Given, 
straight P space equals space open square brackets table row 1 straight alpha 3 row 1 3 3 row 2 4 4 end table close square brackets
|P| = 1(12-12)-α (4-6) +3(4-6)
 = 2α -6.
∵ P =adj(A)
∴ |P| = |adj A | = |A|3-1 = |A|2 = 16
[∵ |adj A| = |A|n-1 order is 3 x3
∴ 2α -6 = 16
2α = 22
α = 11