Question
If P = is the adjoint of a 3 x3 matrix A and |A| = 4, then α is equal to
-
4
-
11
-
5
-
0
Solution
B.
11
Given,
|P| = 1(12-12)-α (4-6) +3(4-6)
= 2α -6.
∵ P =adj(A)
∴ |P| = |adj A | = |A|3-1 = |A|2 = 16
[∵ |adj A| = |A|n-1 order is 3 x3
∴ 2α -6 = 16
2α = 22
α = 11