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Vector Algebra

Question
CBSEENMA12035978

Solve the following differential equation:

2 x2 dydx - 2 x y + y2 = 0

Solution

Here,  2 x2 dydx - 2 x y + y2 = 0                      dydx =  2 x y - y22 x2

Hence the given equation is an homogeneous equation.

Let  y = v x 

and  dydx = v + x dvdxSo,    v + x dvdx = 2 x ( v x ) - ( v x )22 x2                          =  2 v - v2 2 = v - v22     x dvdx = - v22     2  1v2 dv = -  dxx     2 - 1v  = - log  x  + C    2 xy =  log  x  + C

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