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Integrals

Question

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Write the value of $\int \frac{dx}{x^{2} + 16}$

Solution

$\int \frac{dx}{x^{2} + 16} = \int \frac{dx}{(x)^{2} + (4)^{2}} = \frac{1}{4} \tan^{- 1} (\frac{x}{4}) + C, where C is a constant .$

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