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Linear Programming

Question
CBSEENMA12035896

A diet is to contain at least 80 units of Vitamin A and 100 units of minerals. Two foods F1 and F2 are available. Food F1 cost Rs. 4 per unit and F2 costs Rs. 6 per unit. One unit of food F1 contains 3 units of Vitamin A and 4 units of minerals. One unit of food F2 contains 6 units of Vitamin A and 3 units of minerals. Formulate this as a linear programming problem and find graphically the minimum cost for diet that consists of mixture of these two foods and also meets the minerals nutritional requirements.

Solution

Let x be the number of units of food F1 and y be the number of units of food F2.

LPP is,

Minimize  Z = 4x + 6y  such that,

3x + 6y  80

4x + 3y  100

x, y  0

Representing the LPP graphically

                    

Corner points are   0, 1003,  24, 43,  803, 0

 

         

Point cost = 4x + 6y
 0, 1003 4 x 0 + 6 x 1003 = 0 + 200 = 200
 24, 43 4 x 24 + 6 x 43 = 96 + 9 = 104
 803, 0  4 x 803 + 6 x 0 = 3203 + 0 =106.67

 

From the table it is clear that, minimum cost is 104 and occurs at the point  24, 43.