-->

Inverse Trigonometric Functions

Question

Using principal value, evaluate the following: $\sin^{- 1} (\sin \frac{3 π}{5})$

Solution

$As \sin^{- 1} (sinθ) = θ so \sin^{- 1} (\sin (\frac{3 π}{5})) = \frac{3 π}{5} But \frac{3 π}{5} \notin [\frac{- π}{2}, \frac{π}{2}]$

$\sin^{- 1} (\sin (\frac{3 π}{5})) = \sin^{- 1} (\sin (π - \frac{2 π}{5})) = \sin^{- 1} (\sin \frac{2 π}{5}) = \frac{2 π}{5} \in [\frac{- π}{2}, \frac{π}{2}] ∴ Principal value is \frac{2 π}{5}$

For Daily Free Study Material Join wiredfaculty

Inverse Trigonometric Functions

Using principal value, evaluate the following: $\sin^{- 1} (\sin \frac{3 π}{5})$

Some More Questions From Inverse Trigonometric Functions Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Phone Number

Email Address

Loaction

For Daily Free Study Material Join wiredfaculty

Inverse Trigonometric Functions

Using principal value, evaluate the following: sin-1 sin3π5

Some More Questions From Inverse Trigonometric Functions Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Using principal value, evaluate the following: $\sin^{- 1} (\sin \frac{3 π}{5})$