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Vector Algebra

Question
CBSEENMA12035834

Find a unit vector in the direction of  a = 3i ^ - 2j^ + 6k

Solution

The unit vector a^ in the direction of a is given by aaa^ = 3i^ - 2j^ + 6k^32 + (-2)2 + 62   = 3i^ - 2j^ + 6k^9+ 4 + 36  = 3i^ - 2j^ + 6k^49  = 173i^ - 2j^ + 6k^ =  37i^ - 27j^ + 67k^