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Matrices

Question
CBSEENMA12035824

If A = 2-3532-411-2, find A-1. Use it solve the system of equations.

2x - 3y + 5z = 11

3x + 2y - 4z = -5

x + y- 2z =-3

Solution

A = 2-3533-411-2 |A| = 2 (-4 + 4) + 3 (-6 + 4) + 5 (3-2) = 0 - 6 + 5 = -1 0

Now, A11 0, A12 = 2., A12 =1

A21 = -1, A22 = -9, A23 = -5

A31 = 2, A32 = 23, A33 = 13

 A-1 = 1|A|(adj A) = - 0-122-9231-513 = 01-2-29-23-15-13 ... (1)

Now, the given system of equations can be written in the form of AX = B, where

A = 2-3532-411-2, X  = xyz and B = 11-5-3The solution of the system of equations is given by X = A-1BX = A-1Bxyz = 01-2-29-23-15-1311-5-3 (using 1) = 0-5 + 6-22-45+39-11-25+39123