-->

Differential Equations

Question

Wired Faculty App

If $(x^{2} + y^{2})^{2} = xy, find \frac{dy}{dx}$

Solution

Given:

$(x^{2} + y^{2})^{2} = xy x^{4} + y^{4} + 2 x^{2} y^{2} = xy diff w . r . t x 4 x^{3} + 4 y^{3} \frac{dy}{dx} + 2 (2 x^{2} y \frac{dy}{dx} + 2 {xy}^{2}) = (x \frac{dy}{dx} + y) 4 y^{3} \frac{dy}{dx} + 4 x^{2} y \frac{dy}{dx} - x \frac{dy}{dx} = y - 4 x^{3} - 4 {xy}^{2} \frac{dy}{dx} (4 y^{3} + 4 x^{2} y - x) = y - 4 x^{3} - 4 {xy}^{2} \frac{dy}{dx} = \frac{y - 4 x^{3} - 4 {xy}^{2}}{4 y^{3} + 4 x^{2} y - x}$

For Daily Free Study Material Join wiredfaculty

Differential Equations

If $(x^{2} + y^{2})^{2} = xy, find \frac{dy}{dx}$

Some More Questions From Differential Equations Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Phone Number

Email Address

Loaction

For Daily Free Study Material Join wiredfaculty

Differential Equations

If (x2 + y2)2 = xy, find dydx

Some More Questions From Differential Equations Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

If $(x^{2} + y^{2})^{2} = xy, find \frac{dy}{dx}$