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If θ is the angle between two vectors i^ - 2j^ + 3k^ and 3i^ - 2j^ + k^ find sin θ.
a→ = i^ - 2j^ + 3k^b→ = 3i^ - 2j^ + k^a→ x b→ = i^j^k^1-233-21 = (4)i^ + 8j^ + 4k^|a→ x b→| = (4)2 + (8)2 + (4)2 = 16 + 64 + 16 = 96= 46|a→| = 12 + (-2)2 + 32 = 14|b→| = 32 + (-2)2 + 12 = 14∵ |a→ x b→| = |a→||b→| sin θwhere θ is the angle between a→ and b→⇒ sin θ = 461414 = 4614 = 276sin θ = 276
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