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Inverse Trigonometric Functions

Question

Find the value of $\tan^{- 1} \sqrt{3} - c o t^{- 1} (- \sqrt{3})$

Solution

$\tan^{- 1} (\sqrt{3}) - \cot^{- 1} (- \sqrt{3}) = y as \cot^{- 1} (- x) = π - \cot^{- 1} x ∴ y = \tan^{- 1} (\sqrt{3}) - (π - \cot^{- 1} (\sqrt{3})) = \frac{π}{3} - (π - \frac{π}{6}) = \frac{π}{3} - π + \frac{π}{6} = \frac{π}{2} - π = - \frac{π}{2}$

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Inverse Trigonometric Functions

Find the value of $\tan^{- 1} \sqrt{3} - c o t^{- 1} (- \sqrt{3})$

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Inverse Trigonometric Functions

Find the value of tan-1 3 - cot-1 (-3)

Some More Questions From Inverse Trigonometric Functions Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Find the value of $\tan^{- 1} \sqrt{3} - c o t^{- 1} (- \sqrt{3})$