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Integrals

Question
CBSEENMA12035770

Find space integral fraction numerator dx over denominator straight x squared space plus 4 straight x space plus 8 end fraction

Solution
integral fraction numerator 1 over denominator straight x squared space plus 4 straight x space 8 end fraction dx
straight I space equals space integral fraction numerator 1 over denominator straight x squared plus 4 straight x space plus 8 end fraction dx
equals space integral fraction numerator 1 over denominator left parenthesis straight x plus 2 right parenthesis squared space plus 2 squared end fraction dx
By space using space Integral space Formula
integral fraction numerator 1 over denominator straight x squared space plus straight a squared end fraction space dx space equals space 1 over straight a tan to the power of negative 1 end exponent open parentheses straight x over straight a close parentheses
equals 1 half tan to the power of negative 1 end exponent open parentheses fraction numerator straight x plus 2 over denominator 2 end fraction close parentheses space plus straight C

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