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Integrals

Question
CBSEENMA12035767

Find the vector equation of the line passing through the point A(1, 2, –1) and parallel to the line 5x – 25 = 14 – 7y = 35z.

Solution

The equation of the line 5x-25 =14-7y =35z can be rewritten as
fraction numerator straight x minus 5 over denominator 1 end fraction space equals space fraction numerator straight y minus 2 over denominator negative 1 end fraction space equals fraction numerator straight z over denominator 1 divided by 35 end fraction
rightwards double arrow fraction numerator straight x minus 5 over denominator 7 end fraction space equals space fraction numerator straight y minus 2 over denominator negative 5 end fraction space equals straight z over 1
Since the required line is parallel to the given line, so the direction ratio of the required line is proportional to 7,-5,1
The vector equation of the required line passing through the point (1,2-1) and having direction ratios proportional to 7,-5 1 is
straight r with rightwards arrow on top space equals space left parenthesis straight i with hat on top space plus 2 straight j with hat on top minus straight k with hat on top right parenthesis space plus straight lambda left parenthesis 7 straight i with hat on top space minus 5 straight j with hat on top plus straight k with hat on top right parenthesis

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