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Vector Algebra

Question
CBSEENMA12035747

Find the coordinates of the point, where the line fraction numerator straight x minus 2 over denominator 3 end fraction equals fraction numerator straight y plus 1 over denominator 4 end fraction equals fraction numerator straight z minus 2 over denominator 2 end fraction intersects the plane straight x minus straight y plus straight z minus 5 space equals space 0. Also find the angle between the line and the plane. 

Solution

The equation of the given line is fraction numerator straight x minus 2 over denominator 3 end fraction equals space fraction numerator straight y plus 1 over denominator 4 end fraction equals fraction numerator straight z minus 2 over denominator 2 end fraction space space... left parenthesis 1 right parenthesis
Any point on the given line is left parenthesis 3 straight lambda plus 2 comma space 4 straight lambda minus 1 comma space 2 straight lambda plus 2 right parenthesis.
If this point lies on the given plane x - y + z - 5 = 0, then
3 straight lambda plus 2 minus left parenthesis 4 straight lambda minus 1 right parenthesis plus 2 straight lambda plus 2 minus 5 space equals space 0
rightwards double arrow straight lambda space equals space 0
Putting straight lambda space equals space 0 in left parenthesis 3 straight lambda plus 2 comma space 4 straight lambda minus 1 comma space 2 straight lambda plus 2 right parenthesis comma we get the point of intersection of the given line and the plane is (2, -1, 2).
Let straight theta be the angle between the given line and the plane. 
therefore space space sin space straight theta space equals space fraction numerator straight a with rightwards arrow on top. straight b with rightwards arrow on top over denominator open vertical bar straight a with rightwards arrow on top close vertical bar open vertical bar straight b with rightwards arrow on top close vertical bar end fraction space equals fraction numerator left parenthesis 3 straight i with rightwards arrow on top plus 4 straight j with rightwards arrow on top plus 2 stack straight k right parenthesis with rightwards arrow on top. left parenthesis straight i with rightwards arrow on top minus straight j with rightwards arrow on top plus straight k with rightwards arrow on top right parenthesis over denominator square root of 3 squared plus 4 squared plus 2 squared end root square root of 1 squared plus 1 squared plus 1 squared end root end fraction equals fraction numerator 3 minus 4 plus 2 over denominator square root of 29 square root of 3 end fraction equals fraction numerator 1 over denominator square root of 87 end fraction
rightwards double arrow straight theta space equals sin to the power of negative 1 end exponent open parentheses fraction numerator 1 over denominator square root of 87 end fraction close parentheses
Thus, the angle between the given line and the given plane is sin to the power of negative 1 end exponent open parentheses fraction numerator 1 over denominator square root of 87 end fraction close parentheses.