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Integrals

Question
CBSEENMA12035745

Evaluate: integral subscript 0 superscript 4 open parentheses open vertical bar straight x close vertical bar plus open vertical bar straight x minus 2 close vertical bar plus open vertical bar straight x minus 4 close vertical bar close parentheses dx

Solution
integral subscript 0 superscript 4 open square brackets open vertical bar straight x close vertical bar plus open vertical bar straight x minus 2 close vertical bar plus open vertical bar straight x minus 4 close vertical bar close square brackets dx
equals integral subscript 0 superscript 2 straight f left parenthesis straight x right parenthesis dx plus integral subscript 2 superscript 4 straight f left parenthesis straight x right parenthesis dx
equals integral subscript 0 superscript 2 left parenthesis straight x minus straight x plus 2 minus straight x plus 4 right parenthesis dx plus integral subscript 2 superscript 4 left parenthesis straight x plus straight x minus 2 minus straight x plus 4 right parenthesis dx
equals integral subscript 0 superscript 2 left parenthesis 6 minus straight x right parenthesis dx plus integral subscript 2 superscript 4 left parenthesis straight x plus 2 right parenthesis dx
equals open square brackets 6 straight x minus straight x squared over 2 close square brackets subscript 0 superscript 2 plus open square brackets straight x squared over 2 plus 2 straight x close square brackets subscript 2 superscript 4
equals open square brackets 12 minus 2 close square brackets plus open square brackets 8 plus 8 minus 2 minus 4 close square brackets equals 20

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