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Probability

Question
CBSEENMA12035709

An experiment succeeds thrice as often as it fails. Find the probability that in the next five trials, there will be at least 3 successes.

Solution

An experiment succeeds as often as it fails.
Therefore, there are 3 successes and 1 failures.
Thus the probability of success equals 3 over 4
And the probability of failure = 1 fourth
We need to find the probability of atleast 3 successes in the next five trials.
Required Probability  = P(X= 3) + P(X = 4) + P(X = 5)
equals straight C presuperscript 5 subscript 3 straight p cubed straight q squared space plus space straight C presuperscript 5 subscript 4 straight p to the power of 4 straight q to the power of 1 space plus space straight C presuperscript 5 subscript 5 straight p to the power of 5 straight q to the power of 0
equals straight C presuperscript 5 subscript 3 open parentheses 3 over 4 close parentheses cubed open parentheses 1 fourth close parentheses squared space plus space straight C presuperscript 5 subscript 4 open parentheses 3 over 4 close parentheses to the power of 4 open parentheses 1 fourth close parentheses to the power of 1 space plus straight C presuperscript 5 subscript 5 open parentheses 3 over 4 close parentheses to the power of 5 open parentheses 1 fourth close parentheses to the power of 0
equals 10 open parentheses 3 over 4 close parentheses cubed open parentheses 1 fourth close parentheses squared plus 5 open parentheses 3 over 4 close parentheses to the power of 4 open parentheses 1 fourth close parentheses to the power of 1 plus open parentheses 3 over 4 close parentheses to the power of 5 open parentheses 1 fourth close parentheses to the power of 0
equals 918 over 1024
equals 459 over 512

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