Sponsor Area

Application Of Derivatives

Question
CBSEENMA12035618

Find the approximate change in the surface area of a cube of side x metres caused by decreasing the side by 1%.

Solution
Let S be surface area of cube of side x metre.
therefore space space space space space space space straight S space equals space 6 straight x squared
Now,    dS space equals space open parentheses dS over dx close parentheses increment straight x space equals space 12 space straight x space increment straight x
space space space space
               equals 12 straight x left parenthesis negative 0.01 space straight x right parenthesis space space space space space space space space space space space space space space space space space space space open square brackets because space space 1 percent sign space of space straight x space is space 0.01 space straight x close square brackets
equals space minus 0.12 space straight x squared
therefore space space space space approximate space change space in space volume space equals space 0.12 space straight x squared space straight m squared left parenthesis numerically right parenthesis.