Inverse Trigonometric Functions

Name: Wired Faculty - The Best Learning App
Rating: 4.6 (1864 reviews)

Question

Show that:
$2 sin to the power of negative 1 end exponent open parentheses 3 over 5 close parentheses minus tan to the power of negative 1 end exponent open parentheses 17 over 31 close parentheses equals space straight pi over 4$

Solution

2 sin to the power of negative 1 end exponent open parentheses 3 over 5 close parentheses minus tan to the power of negative 1 end exponent open parentheses 17 over 31 close parentheses space equals straight pi over 4 straight L. straight H. straight S. comma space space space equals cos to the power of negative 1 end exponent open parentheses 1 minus 2 cross times 9 over 25 close parentheses minus tan to the power of negative 1 end exponent open parentheses 17 over 31 close parentheses space space space equals cos to the power of negative 1 end exponent open parentheses 7 over 25 close parentheses minus tan to the power of negative 1 end exponent open parentheses 17 over 31 close parentheses space space space space equals tan to the power of negative 1 end exponent open parentheses 24 over 7 close parentheses minus tan to the power of negative 1 end exponent open parentheses 17 over 31 close parentheses space space space space space equals tan to the power of negative 1 end exponent open parentheses 24 over 7 close parentheses minus tan to the power of negative 1 end exponent open parentheses 17 over 31 close parentheses space space space space space equals tan to the power of negative 1 end exponent open parentheses fraction numerator begin display style 24 over 7 end style minus begin display style 17 over 31 end style over denominator 1 plus begin display style 24 over 7 end style cross times begin display style 17 over 31 end style end fraction close parentheses space space space space space equals tan to the power of negative 1 end exponent open parentheses fraction numerator 24 cross times 31 minus 17 cross times 7 over denominator 31 cross times 7 plus 24 cross times 17 end fraction close parentheses space space space space space space equals tan to the power of negative 1 end exponent open parentheses 625 over 625 close parentheses space space space space space space equals tan to the power of negative 1 end exponent 1 space space space space space space equals straight pi over 4 space space space space space equals straight R. straight H. straight S space space space space space Hence space Proved

For Daily Free Study Material Join wiredfaculty

Inverse Trigonometric Functions

Show that:
$2 sin to the power of negative 1 end exponent open parentheses 3 over 5 close parentheses minus tan to the power of negative 1 end exponent open parentheses 17 over 31 close parentheses equals space straight pi over 4$

Some More Questions From Inverse Trigonometric Functions Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Phone Number

Email Address

Loaction