Question

Verify Roll's Theorem for the function : $straight f left parenthesis straight x right parenthesis equals space sin space 2 space straight x space or space cos space 2 open parentheses straight x minus straight pi over 4 close parentheses space in space open square brackets 0 comma space straight pi over 2 close square brackets$

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Solution

Here space straight f left parenthesis straight x right parenthesis equals space sin space 2 space straight x left parenthesis straight a right parenthesis space Since space sine space curve space is space continuous space therefore space space straight f left parenthesis straight x right parenthesis space is space straight a space continuous space function space in space straight f open square brackets 0 comma space straight pi over 2 close square brackets left parenthesis straight b right parenthesis space straight f apostrophe left parenthesis 0 right parenthesis equals space 2 space cos space 2 straight x comma space which space exixts space in space open parentheses 0 comma space straight pi over 2 close parentheses space rightwards double arrow space straight f left parenthesis straight x right parenthesis space is space derivable space in space open parentheses 0 comma space straight pi over 2 close parentheses left parenthesis straight c right parenthesis space space straight f left parenthesis 0 right parenthesis equals space sin space 0 equals 0 therefore space space straight f open parentheses straight pi over 2 close parentheses equals sin space straight pi equals 0 therefore space space straight f left parenthesis 0 right parenthesis space equals straight f open parentheses straight pi over 2 close parentheses therefore space space straight f left parenthesis straight x right parenthesis space satisfies space all space the space conditions space of space Rolle apostrophe straight s space Theorem. therefore space space there space must space exists space at space least space one space value space straight c space of space straight x space such space that space straight f apostrophe left parenthesis straight c right parenthesis equals 0 space where space straight c element of space open parentheses 0 comma space straight pi over 2 close parentheses Now space straight f apostrophe left parenthesis straight c right parenthesis equals 2 space cos space 2 straight c therefore space straight f apostrophe left parenthesis straight c right parenthesis equals 0 space gives space us space space 2 space cos space 2 straight c equals 0 comma space straight i. straight e. comma space cos space 2 straight c equals 0 straight i. straight e. comma space space 2 straight c equals straight pi over 2 space or space straight c equals straight pi over 4 space lies space in space open parentheses 0 comma space straight pi over 2 close parentheses therefore space space rolle apostrophe straight s space Theorem space is space verified.

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