Question
Find the absolute maximum value and the absolute minimum value of
Solution
The function is differentiable for all x in
and
Now,
i.e., when (x - 5) (x - 1) = 0
i.e., when x = 1 or x = 5
But only
Now,
Hence absolute maximum value is and absolute minimum value is
. These are attained at 1 and 4 respectively.