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Application Of Derivatives

Question
CBSEENMA12035342

Separate open square brackets 0 comma space space space straight pi over 2 close square brackets into sub-intervals in which the function f (x) = sin 3x is increasing or decreasing.

Solution

Here straight f left parenthesis straight x right parenthesis space equals space sin space 3 straight x space space space space space space space rightwards double arrow space space space space space straight f apostrophe left parenthesis straight x right parenthesis space equals space 3 space cos space 3 straight x
(i) For f(x) to be increasing,  f '(x) > 0 
therefore space space space space 3 space cos space 3 straight x space greater than 0 space space space space space space space space space space rightwards double arrow space space space space cos space 3 straight x space greater than 0 space space space space space space space space rightwards double arrow space space space space straight x space element of space open parentheses 0 comma space space straight pi over 6 close parentheses
therefore space space space space straight f left parenthesis straight x right parenthesis space increases space in space open parentheses 0 comma space straight pi over 6 close parentheses
(ii) For f(x) to be decreasing,   f '(x) < 0
therefore space space space space 3 space cos space 3 straight x space less than 0 space space space space space rightwards double arrow space space space space cos space 3 straight x space less than space 0 space space space space space space space space rightwards double arrow space straight x space element of space space space open parentheses straight pi over 6 comma space space straight pi over 2 close parentheses
therefore space space space space straight f left parenthesis straight x right parenthesis space decreases space in space open parentheses straight pi over 6 comma space space straight pi over 2 close parentheses.

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