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Application Of Derivatives

Question
CBSEENMA12035238
Wired Faculty App

The slope of the normal to the curve y = 2 x2 + 3 sin x at x = 0 is

  • 3

  • 1 third

  • -3

  • negative 1 third

Solution

D.

negative 1 third

The equation of curve is
                            y = 2x2 + 3 sin x
therefore space space space space space space space space space dy over dx space equals space 4 space straight x plus 3 space cosx At space space space straight x space equals space 0 comma space space space dy over dx space equals space 4 left parenthesis 0 right parenthesis space plus space 3 space cos space 0 space equals space 0 plus 3 space equals space 3 comma space which space is space slope space of space tangent space to space the space curve. therefore space space space space space space space slope space of space normal space to space the space curve space equals space minus 1 third therefore space space space space space space space left parenthesis straight D right parenthesis space is space correct space answer.

Some More Questions From Application of Derivatives Chapter

The radius of a circle is increasing uniformly at the rate of 4 cm per second Find the rate at which the area of the circle is increasing when the radius is 8 cm.

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