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Continuity And Differentiability

Question
CBSEENMA12035294

Differentiate space the space following space straight w. straight r. straight t. straight x colon space left parenthesis sin space straight x right parenthesis to the power of cos to the power of negative 1 end exponent straight x end exponent

Solution
space space space space space Let space straight y equals left parenthesis sin space straight x right parenthesis to the power of cos to the power of negative 1 end exponent straight x end exponent
therefore space log space straight y equals log left parenthesis sin space straight x right parenthesis to the power of cos to the power of negative 1 end exponent straight x end exponent equals cos to the power of negative 1 end exponent straight x. space log space sin space straight x
therefore space 1 over straight y dy over dx equals left parenthesis cos to the power of negative 1 end exponent straight x right parenthesis. fraction numerator cos space straight x over denominator sin space straight x end fraction minus fraction numerator 1 over denominator square root of 1 minus straight x squared end root end fraction. log space sin space straight x
therefore space dy over dx equals open parentheses sin space straight x close parentheses to the power of cos to the power of negative 1 end exponent straight x end exponent open square brackets cot space straight x. space cos to the power of negative 1 end exponent straight x minus fraction numerator log space sin space straight x over denominator square root of 1 minus straight x squared end root end fraction close square brackets

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