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Application Of Derivatives

Question
CBSEENMA12035268

Which of the following function are strictly decreasing on open parentheses 0 comma space straight pi over 2 close parentheses space ?
(a) cos x   (b) cos 2x   (c) cos 3x   (d) tan x

Solution

(a) Let straight f left parenthesis straight x right parenthesis space equals space cos space straight x comma space space space space space space space space therefore space space space straight f apostrophe left parenthesis straight x right parenthesis space equals space minus sin space straight x space
In open parentheses 0 comma space straight pi over 2 close parentheses comma space space straight f apostrophe left parenthesis straight x right parenthesis space equals space minus sin space straight x space less than space 0
 therefore space space space space straight f left parenthesis straight x right parenthesis space equals space cosx space is space strictly space decreasing space on space open parentheses 0 comma space straight pi over 2 close parentheses
(b) Let straight f left parenthesis straight x right parenthesis space equals space cos space 2 straight x comma space space space space space space therefore space space space space space straight f apostrophe left parenthesis straight x right parenthesis space equals space minus 2 space sin space 2 straight x
In open parentheses 0 comma space straight pi over 2 close parentheses comma space space space straight f apostrophe left parenthesis straight x right parenthesis space equals space minus 2 space sin space 2 straight x space less than space 0
therefore space space space space space straight f left parenthesis straight x right parenthesis space equals space cos space 2 straight x is strictly decreasing on open parentheses 0 comma space straight pi over 2 close parentheses.
(c)  Let f(x) = cos 3x,       therefore space space space straight f apostrophe left parenthesis straight x right parenthesis space equals space minus 3 space sin space 3 straight x
                           0 less than straight x less than straight pi over 2
rightwards double arrow space space space space space space 0 less than space 3 straight x space less than space fraction numerator 3 straight pi over denominator 2 end fraction
Now  straight f apostrophe left parenthesis straight x right parenthesis space less than 0 space space space space when space 0 space less than space 3 straight x space less than space straight pi
and straight f apostrophe left parenthesis straight x right parenthesis space greater than 0 space space space when space straight pi space less than space 3 straight x space less than fraction numerator 3 straight pi over denominator 2 end fraction
therefore space space space space space straight f left parenthesis straight x right parenthesis space is space not space straight a space strictly space decreasing space function space on space open parentheses 0 comma space space straight pi over 2 close parentheses
(d) Let straight f left parenthesis straight x right parenthesis space equals tanx comma space space space space space space space space therefore space space space space space straight f apostrophe left parenthesis straight x right parenthesis space equals space sec squared straight x
Now,    straight f apostrophe left parenthesis straight x right parenthesis greater than 0 space space for all space straight x space space space space element of space space space open parentheses 0 comma space space straight pi over 2 close parentheses
therefore space space space straight f left parenthesis straight x right parenthesis space is space not space straight a space strictly space decreasing space function space on space open parentheses 0 comma space space space straight pi over 2 close parentheses