Question
The normal to the curve x2 = 4 y passing (1, 2) is
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x + y = 3
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x – y = 3
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x + y = 1
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x – y = 1
Solution
A.
x + y = 3The equation of the curve is ...(1)
Let normal at (h, k) pass through (1, 2).
Since (h, k) lies on (1)
...(2)
Slope of tangent at (h, k) =
Equation of normal at (h, k) is
or
From (2) and (3), we get,