+91-8076753736[email protected]
logo
logo
-->

Application Of Derivatives

Question
CBSEENMA12035115
Wired Faculty App

Find the equation of the tangent and normal to the given curves at the points given:
y2 = 4ax at (0, 0).

Solution

The equation of curve is y2 = 4ax
Differentiating both sides w.r.t.x,   2 straight y dy over dx space equals space 4 straight a space space space space space space space rightwards double arrow space space space space space dy over dx space equals space fraction numerator 2 straight a over denominator straight y end fraction
At (0, 0) dy over dx does not exist
therefore space space space space space tangent space at space left parenthesis 0 comma space 0 right parenthesis space is space vertical therefore space space space space its space equation space is space straight x space equals space 0

Some More Questions From Application of Derivatives Chapter

The radius of a circle is increasing uniformly at the rate of 4 cm per second Find the rate at which the area of the circle is increasing when the radius is 8 cm.

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation