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Application Of Derivatives

Question
CBSEENMA12035114
Wired Faculty App

Find the equation of the tangent and normal to the given curves at the points given:
y = x2 at (0,0).

Solution

The equations of curve is y = x2              rightwards double arrow space space space space space space space space space dy over dx space equals space 2 straight x
At space left parenthesis 0 comma space 0 right parenthesis space dy over dx space equals space 2 left parenthesis 0 right parenthesis space equals space 0 therefore space space space space space straight m space equals space 0 comma space space space space where space straight m space is space slope space of space tangent. therefore space space space space space space the space equation space of space tangent space at space left parenthesis 0 comma space 0 right parenthesis space is space space space space space space space space space space space space space space straight y minus 0 space equals space 0 left parenthesis straight x minus 0 right parenthesis space space space space or space space space straight y space equals space 0 Now space the space normal space passes space through space the space origin space and space is space perpendicular space to space the space tangent space straight y space equals 0 therefore space space space space space space its space equation space is space straight x space equals 0
   

Some More Questions From Application of Derivatives Chapter

The radius of a circle is increasing uniformly at the rate of 4 cm per second Find the rate at which the area of the circle is increasing when the radius is 8 cm.

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