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Continuity And Differentiability

Question
CBSEENMA12035103

Differentiate the following function w.r.t.x:sin minus 1 left parenthesis cos space straight x right parenthesis comma space 0 less than straight x less than straight pi over 2

Solution
Let space space space space space straight y equals sin minus 1 left parenthesis cos space straight x right parenthesis
therefore space dy over dx equals fraction numerator 1 over denominator square root of 1 minus cos squared straight x end root end fraction. straight d over dx left parenthesis cos space straight x right parenthesis equals fraction numerator 1 over denominator sin space straight x end fraction. left parenthesis negative sin space straight x right parenthesis equals negative 1

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