Sponsor Area

Continuity And Differentiability

Question
CBSEENMA12035189

Differentiate the following w.r.t.x: sin to the power of negative 1 end exponent left parenthesis 3 straight x minus 4 straight x cubed right parenthesis comma space minus 1 half less than straight x less than 1 half

Solution
Let space space straight y equals sin to the power of negative 1 end exponent left parenthesis 3 straight x minus 4 straight x cubed right parenthesis semicolon space Put space straight x equals sin space straight theta
therefore space space space space straight y equals sin to the power of negative 1 end exponent left parenthesis 3 sin space straight theta minus 4 sin cubed space straight theta right parenthesis equals sin to the power of negative 1 end exponent left parenthesis sin space 3 straight theta right parenthesis equals 3 straight theta
therefore space space space space straight y equals 3 space sin to the power of negative 1 end exponent straight x space space rightwards double arrow space dy over dx equals fraction numerator 3 over denominator square root of 1 minus straight x squared end root end fraction

Some More Questions From Continuity and Differentiability Chapter