+91-8076753736 support@wiredfaculty.com
logo
logo

Sponsor Area

Continuity And Differentiability

Question
CBSEENMA12035038
Wired Faculty App

Differentiate (log x)cos x w.r.t. x.

Solution
Let space space space space space space space space straight y equals left parenthesis log space straight x right parenthesis to the power of cos space straight x end exponent therefore space space log space straight y equals log left parenthesis log space straight x right parenthesis to the power of cos space straight x end exponent rightwards double arrow space log space straight y equals cos space straight x. log left parenthesis log space straight x right parenthesis Differentiating space both space sides space straight w. straight r. straight t. straight x comma space we space get comma space 1 over straight y dy over dx equals cos space straight x. open parentheses fraction numerator 1 over denominator log space straight x end fraction.1 over straight x close parentheses plus log left parenthesis log space straight x right parenthesis. left parenthesis negative sin space straight x right parenthesis therefore space space dy over dx equals straight y open square brackets fraction numerator cos space straight x over denominator straight x space log space straight x end fraction minus sin space straight x. log left parenthesis log space straight x right parenthesis close square brackets therefore space space dy over dx equals left parenthesis log space straight x right parenthesis to the power of cos space straight x end exponent open square brackets fraction numerator cos space straight x over denominator straight x space log space straight x end fraction minus sin space straight x. log left parenthesis log space straight x right parenthesis close square brackets

Some More Questions From Continuity and Differentiability Chapter

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation