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Sponsor Area

Continuity And Differentiability

Question
CBSEENMA12035022

space space space space space space space space space space space straight x equals cosө minus cos 2 straight ө comma space space space space straight y equals sinө minus sin 2 straight ө
therefore space dx over dθ equals negative sinθ plus 2 space sinθ
space space space space space dy over dθ equals cosθ minus 2 cosθ
space space space space space dy over dx equals fraction numerator cosθ minus 2 cosθ over denominator negative sinθ plus 2 space sinθ end fraction

Solution

Some More Questions From Continuity and Differentiability Chapter