Question

$Find space dy over dx space when space straight x equals straight a left parenthesis 1 minus cosθ right parenthesis comma space straight y equals straight a left parenthesis straight theta plus sinθ right parenthesis$

Name: Wired Faculty - The Best Learning App
Rating: 4.6 (1864 reviews)

Solution

Here space space space space space straight x equals straight a left parenthesis 1 minus cosθ right parenthesis comma space space straight y equals straight a left parenthesis straight theta plus sinθ right parenthesis therefore space space space space dx over dθ equals straight a space sinθ comma space space dy over dθ equals straight a left parenthesis 1 plus cosθ right parenthesis Now space dy over dx equals fraction numerator begin display style dy over dθ end style over denominator begin display style dx over dθ end style end fraction equals fraction numerator straight a left parenthesis 1 plus cosθ right parenthesis over denominator straight a space sinθ end fraction equals fraction numerator 1 plus cosθ over denominator sinθ end fraction equals fraction numerator 2 cos squared begin display style straight theta over 2 end style over denominator 2 sin begin display style straight theta over 2 end style cos begin display style straight theta over 2 end style end fraction equals fraction numerator cos begin display style straight theta over 2 end style over denominator sin begin display style straight theta over 2 end style end fraction therefore space fraction numerator space space space space dy over denominator dx end fraction equals cot straight theta over 2

For Daily Free Study Material Join wiredfaculty