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Application Of Derivatives

Question
CBSEENMA12035092

Find the equation of tangent to the curve:
straight x space equals space straight theta plus space sin space straight theta comma space space space straight y space equals space 1 plus space cos space straight theta space space at space straight theta equals space straight pi over 4

Solution

The equations of curve are straight x space equals straight theta space plus space sin space straight theta comma space space space space straight y space equals space 1 plus space cos space straight theta
At space straight theta space equals space straight pi over 4 comma space space space straight x space equals space straight pi over 4 plus sin space straight pi over 4 space equals space straight pi over 4 plus fraction numerator 1 over denominator square root of 2 end fraction comma space space space space straight y space equals 1 plus cos space straight pi over 4 space equals space 1 plus fraction numerator 1 over denominator square root of 2 end fraction
therefore space space space space point space of space contact space is space open parentheses straight pi over 4 plus fraction numerator 1 over denominator square root of 2 end fraction comma space space 1 plus fraction numerator 1 over denominator square root of 2 end fraction space close parentheses.
space space space space space space space space space space space space space space space dx over dθ space equals space 1 plus cos space straight theta. space dy over dθ space equals space minus sin space straight theta
space space space space dy over dx space equals space fraction numerator begin display style dy over dθ end style over denominator begin display style dx over dθ end style end fraction space equals space minus fraction numerator sin space straight theta over denominator 1 plus cos space straight theta end fraction
At space space space straight theta space equals space straight pi over 4 comma space dy over dx space equals space minus fraction numerator sin space begin display style straight pi over 4 end style over denominator 1 plus cos space begin display style straight pi over 4 end style end fraction space equals space minus fraction numerator begin display style fraction numerator 1 over denominator square root of 2 end fraction end style over denominator 1 plus begin display style fraction numerator 1 over denominator square root of 2 end fraction end style end fraction space equals negative fraction numerator 1 over denominator square root of 2 plus 1 end fraction comma which is slope of tangent
therefore space space space space space space equation space of space tangent space to space the space curve space at space straight theta space equals space straight pi over 4 space space is
                    straight y minus open parentheses 1 plus fraction numerator 1 over denominator square root of 2 end fraction close parentheses space equals space minus fraction numerator 1 over denominator square root of 2 plus 1 end fraction open square brackets straight x minus open parentheses straight pi over 4 plus fraction numerator 1 over denominator square root of 2 end fraction close parentheses close square brackets
or          straight y minus open parentheses 1 plus fraction numerator 1 over denominator square root of 2 end fraction close parentheses space equals space minus left parenthesis square root of 2 minus 1 right parenthesis space open square brackets straight x minus open parentheses straight pi over 4 plus fraction numerator 1 over denominator square root of 2 end fraction close parentheses close square brackets
                                                               open square brackets because space space space space space fraction numerator 1 over denominator square root of 2 plus 1 end fraction space equals space fraction numerator 1 over denominator square root of 2 plus 1 end fraction cross times fraction numerator square root of 2 minus 1 over denominator square root of 2 minus 1 end fraction space equals space fraction numerator square root of 2 minus 1 over denominator 2 minus 1 end fraction space equals space square root of 2 minus 1 close square brackets

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