Sponsor Area

Continuity And Differentiability

Question
CBSEENMA12034974

If cosy = x cos (a + y), then prove thatdy over dx equals fraction numerator cos squared left parenthesis straight a plus straight y right parenthesis over denominator sin space straight a end fraction

Solution
because space space cos space straight y equals straight x space cos left parenthesis straight a plus straight y right parenthesis
therefore space space space space space space space space space space straight x equals fraction numerator cos space straight y over denominator cos left parenthesis straight a plus straight y right parenthesis end fraction
Differentiating space both space sides space straight w. straight r. straight t. space straight y comma
space space space space space space space space space dx over dy equals fraction numerator cos left parenthesis straight a plus straight y right parenthesis. begin display style straight d over dy end style left parenthesis cos space straight y right parenthesis minus cos space straight y begin display style straight d over dy end style left square bracket cos left parenthesis straight a plus straight y right parenthesis right square bracket over denominator cos squared left parenthesis straight a plus straight y right parenthesis end fraction
therefore space space space space space dy over dx equals negative fraction numerator cos left parenthesis straight a plus straight y right parenthesis sin space straight y plus cos space straight y space sin left parenthesis straight a plus straight y right parenthesis over denominator cos squared left parenthesis straight a plus straight y right parenthesis end fraction
space space space space space space space space space space space space space space space space space equals fraction numerator sin left square bracket left parenthesis straight a plus straight y right parenthesis minus straight y right square bracket over denominator cos squared left parenthesis straight a plus straight y right parenthesis end fraction equals fraction numerator sin space straight a over denominator cos squared left parenthesis straight a plus straight y right parenthesis end fraction
Now space dy over dx equals fraction numerator 1 over denominator begin display style dx over dy end style end fraction equals fraction numerator cos squared left parenthesis straight a plus straight y right parenthesis over denominator sin space straight a end fraction

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