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Application Of Derivatives

Question
CBSEENMA12034967

The total cost C(x) in Rupees,   associated with the production of x units of an item is given by C(x) = 0.005 x- 0.02 x+ 30 x + 5000.
Find the marginal cost when 3 units are produced, where by marginal cost we mean the instantaneous rate of change of total cost at any level of output.

Solution

Here C(x) = 0.005 x- 0.02 x+ 30 x + 5000
therefore space space space space space straight C space equals space 0.005 space straight x cubed minus space space 0.02 space straight x squared space plus space 30 space straight x space plus space 5000
 Marginal cost = dC over dx space equals space 3 left parenthesis 0.005 right parenthesis space straight x squared minus space 2. space left parenthesis 0.02 right parenthesis space straight x space space plus space 30
    When x = 3,   Marginal cost = 3 (0.005) (3) - 2 (0.02) (3) + 30
                                                 = 27(0.005) - 6 (0.02) + 30
                                                  =0.0135 - 0.12 + 30 = 30.015 = Rs. 30.02 nearly