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Application Of Derivatives

Question
CBSEENMA12034960

Find the rate of change of the volume of a ball with respect to its radius r. How fast is the volume changing with respect to the radius when the radius is 2 m?

Solution
Let V be volume of ball of radius r
therefore space space space space space space space space space straight V equals space 4 over 3 πr cubed
Rate of change of volume with respect to straight r space equals space dV over dr
                                equals space straight d over dr open parentheses 4 over 3 πr cubed close parentheses space equals space 4 over 3 straight pi straight d over dr left parenthesis straight r cubed right parenthesis space equals fraction numerator 4 straight pi over denominator 3 end fraction cross times 3 straight r squared space equals space 4 πr squared
When r = 2 m, rate of change of volume = 4 straight pi (2)2 = 16 straight pi m3/m.

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