+91-8076753736 support@wiredfaculty.com

Sponsor Area

Continuity And Differentiability

Question

Wired Faculty App

Differentiate the following w.r.t.x: $fraction numerator cot squared straight x minus 1 over denominator cot squared straight x plus 1 end fraction$

Solution

Let space space space space straight y equals fraction numerator cot squared straight x minus 1 over denominator cot squared straight x plus 1 end fraction equals fraction numerator begin display style fraction numerator 1 over denominator tan squared straight x end fraction end style minus 1 over denominator begin display style fraction numerator 1 over denominator tan squared plus 1 end fraction end style end fraction equals fraction numerator 1 minus tan squared straight x over denominator 1 plus tan squared straight x end fraction therefore space space space space space space straight y equals cos space 2 straight x therefore space dy over dx equals negative 2 sin space 2 straight x

Some More Questions From Continuity and Differentiability Chapter

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation