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Determinants

Question
CBSEENMA12034948

The cost of 4 kg. onion, 3 kg. wheat and 2 kg. rice is Rs. 60. The cost of 2 kg. onion, 4 kg. wheat and 6 kg. rice is Rs. 90. The cost of 6 kg. onion. 2 kg. wheat and 3 kg. rice is Rs. 70. Find cost of each item per kg. by matrix method.

Solution

Let the cost of onion, wheat and rice per kg. be Rs. ,v, Rs. y and Rs. r respectively.
From given conditions,
4x + 3y + 2z = 60
2x + 4y + 6z = 90
6x + 2y + 3z = 70
These equations can be written as
                        open square brackets table row 4 cell space space space 3 end cell cell space space space 2 end cell row 2 cell space space space 4 end cell cell space space space 6 end cell row 6 cell space space space 2 end cell cell space space 3 end cell end table close square brackets space open square brackets table row straight x row straight y row straight z end table close square brackets space equals space open square brackets table row 60 row 90 row 70 end table close square brackets
   or space space space space space space space space AX space equals space straight B space space where space straight A space equals space open square brackets table row 4 cell space space space 3 end cell cell space space space 2 end cell row 2 cell space space space 4 end cell cell space space space 6 end cell row 6 cell space space space 2 end cell cell space space space 3 end cell end table close square brackets comma space space space space straight X space equals space open square brackets table row straight x row straight y row straight z end table close square brackets comma space space space straight B space equals space open square brackets table row 60 row 90 row 70 end table close square brackets
 open vertical bar straight A close vertical bar space equals space open vertical bar table row 4 cell space space 3 end cell cell space space space 2 end cell row 2 cell space space 4 end cell cell space space space 6 end cell row 6 cell space space 2 end cell cell space space space 3 end cell end table close vertical bar space equals space 4 open vertical bar table row 4 cell space space space 6 end cell row 2 cell space space space 3 end cell end table close vertical bar minus 3 space open vertical bar table row 2 cell space space space space 6 end cell row 6 cell space space space 3 end cell end table close vertical bar plus space 2 space open vertical bar table row 2 cell space space space space 4 end cell row 6 cell space space space space 2 end cell end table close vertical bar
space space space space space space space equals space 4 left parenthesis 12 minus 12 right parenthesis space minus space 3 left parenthesis 6 minus 36 right parenthesis space plus space 2 left parenthesis 4 minus 24 right parenthesis
space space space space space space space space equals 4 left parenthesis 0 right parenthesis space minus space 3 left parenthesis negative 30 right parenthesis space plus space 2 left parenthesis negative 20 right parenthesis space equals space 0 plus 90 minus 40 space equals space 50 space not equal to space 0
therefore space space space space space straight A to the power of negative 1 end exponent space exists.
Co-factors of the elements of first row of | A | are   
  open vertical bar table row 4 cell space space space 6 end cell row 2 cell space space 3 end cell end table close vertical bar comma space space space space minus open vertical bar table row 2 cell space space space space 6 end cell row 6 cell space space space space 3 end cell end table close vertical bar comma space space open vertical bar table row 2 cell space space space space 4 end cell row 6 cell space space space space 2 end cell end table close vertical bar
i.e. (12 – 12), – (6 – 36), (4 – 24)   i.e. 0,  30, – 20 respectively.
Co-factors of the elements of second row of | A | are
negative open vertical bar table row 3 cell space space space 2 end cell row 2 cell space space space 3 end cell end table close vertical bar comma space space open vertical bar table row 4 cell space space space space 2 end cell row 6 cell space space space 3 end cell end table close vertical bar comma space space space space minus open vertical bar table row 4 cell space space space 3 end cell row 6 cell space space space 2 end cell end table close vertical bar
i.e. – (9 – 4), (12 – 12), – (8 - 18) i.e. – 5, 0, 10 respectively.
Co-factors of the elements of third row of | A | are
open vertical bar table row 3 cell space space space 2 end cell row 4 cell space space space 6 end cell end table close vertical bar comma space space space minus open vertical bar table row 4 cell space space space 2 end cell row 2 cell space space space 6 end cell end table close vertical bar comma space space space open vertical bar table row 4 cell space space space 3 end cell row 2 cell space space space 4 end cell end table close vertical bar
i.e. (18 – 8), – (24 – 4), (16 – 6),  i.e. 10, – 20, 10 respectively.
  therefore space space space space space space space space adj. space straight A space equals space open square brackets table row cell space space 0 end cell cell space space space space 30 end cell cell space space space minus 20 end cell row cell negative 5 end cell cell space space space space 0 end cell cell space space space space space 10 end cell row 10 cell space space minus 20 end cell cell space space space space space space 10 end cell end table close square brackets to the power of apostrophe space equals space space open square brackets table row 0 cell space space minus 5 end cell cell space space space space 10 end cell row 30 cell space space space space space 0 end cell cell space minus 20 end cell row cell negative 20 end cell cell space space space space space 10 end cell cell space space space space 10 end cell end table close square brackets space space
therefore space space space straight A to the power of negative 1 end exponent space equals space fraction numerator adj space straight A over denominator open vertical bar straight A close vertical bar end fraction space equals space 1 over 50 open square brackets table row cell space space space 0 end cell cell space space space minus 5 end cell cell space space space space space 10 end cell row cell space space space space 30 end cell cell space space space 0 end cell cell space minus 20 end cell row cell negative 20 end cell cell space space 10 end cell cell space space space 10 end cell end table close square brackets
Now comma space space space space space space space AX space equals space straight B space space space space space rightwards double arrow space space space space space straight X space equals space straight A to the power of negative 1 end exponent straight B
therefore space space space space space space space open square brackets table row straight x row straight y row straight z end table close square brackets space equals space 1 over 50 open square brackets table row 0 cell space space minus 5 end cell cell space space space 10 end cell row 30 cell space space space space 0 end cell cell space minus 20 end cell row cell negative 20 end cell cell space space space 10 end cell cell space space 10 end cell end table close square brackets space open square brackets table row 60 row 90 row 70 end table close square brackets
space space space space space space space space space space space space space space space space space space space equals space 1 over 50 open square brackets table row cell 0 minus 450 plus 700 end cell row cell 1800 plus 0 minus 1400 end cell row cell negative 1200 plus 900 plus 700 end cell end table close square brackets
space space therefore space space space space space space space space space space space space space space space space space space space space equals space 1 over 50 open square brackets table row 5 row 8 row 8 end table close square brackets space space space
therefore space space space space space space space space space space space space space space space space space open square brackets table row straight x row straight y row straight z end table close square brackets space space space equals space open square brackets table row 250 row 400 row 400 end table close square brackets
therefore space space space space space space space space space space space space space space space space space straight x space equals space 5 comma space space space straight y space space equals space 8 comma space space space space straight z space equals space 8.
space
∴   the cost of onion, wheat and rice per kg. are Rs. 5, Rs. 8, Rs. 8 respectively.

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