Sponsor Area

Continuity And Differentiability

Question
CBSEENMA12034938

Differentiate the following functions w.r.t.x:straight e to the power of negative straight x squared end exponent. sin left parenthesis log space straight x right parenthesis

Solution
Let space space space straight y equals straight e to the power of negative straight x squared end exponent. sin left parenthesis log space straight x right parenthesis
space space space dy over dx equals straight e to the power of negative straight x squared end exponent. cos left parenthesis log space straight x right parenthesis.1 over straight x plus sin left parenthesis log space straight x right parenthesis. straight e to the power of negative straight x squared end exponent left parenthesis negative 2 straight x right parenthesis
space space space space space space space space space space space equals straight e to the power of negative straight x squared end exponent open square brackets fraction numerator cos left parenthesis log space straight x right parenthesis over denominator straight x end fraction minus 2 straight x space sin left parenthesis log space straight x right parenthesis close square brackets

Some More Questions From Continuity and Differentiability Chapter