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Continuity And Differentiability

Question
CBSEENMA12034933

Differentiate the following functions w.r.t.x:square root of 1 plus tan space straight x end root

Solution
Let space space space space space straight y equals square root of 1 plus tan space straight x end root
therefore space dy over dx equals fraction numerator 1 over denominator 2 square root of 1 plus tan space straight x end root end fraction. straight d over dx left parenthesis 1 plus tan space straight x right parenthesis equals fraction numerator 1 over denominator 2 square root of 1 plus tan space straight x end root end fraction. sec squared straight x equals fraction numerator sec squared straight x over denominator 2 square root of 1 plus tan space straight x end root end fraction

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