+91-8076753736 support@wiredfaculty.com

Sponsor Area

Continuity And Differentiability

Question

Wired Faculty App

Differentiate the following w.r.t.x: $straight e to the power of 3 straight x end exponent log left parenthesis sin space 2 straight x right parenthesis$

Solution

Let space space space space space straight y equals straight e to the power of 3 straight x end exponent log left parenthesis sin space 2 straight x right parenthesis therefore space dy over dx equals straight e to the power of 3 straight x end exponent. straight d over dx left square bracket log left parenthesis sin space 2 straight x right parenthesis right square bracket plus log left parenthesis 2 sin space straight x right parenthesis. straight d over dx left parenthesis straight e to the power of 3 straight x end exponent right parenthesis space space space space space space space space space space space space space equals straight e to the power of 3 straight x end exponent. fraction numerator 1 over denominator sin space 2 straight x end fraction cross times 2 space cos space 2 straight x plus log left parenthesis sin space 2 straight x right parenthesis.3 straight e to the power of 3 straight x end exponent space space space space space space space space space space space space space equals straight e to the power of 3 straight x end exponent left square bracket 2 space cot space 2 straight x plus 3 log left parenthesis sin space 2 straight x right parenthesis right square bracket

Some More Questions From Continuity and Differentiability Chapter

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation