Question
Solve by matrix method:
Solution
The given equations are:
Put
∴ given equations become
3a + 4b + 7c = 14
2a – b + 3c = 4
a + 2b – 3c = 0
These equations can be written as
or
Put
∴ given equations become
3a + 4b + 7c = 14
2a – b + 3c = 4
a + 2b – 3c = 0
These equations can be written as
or
Co-factors of the elements of first row of | A | are
i.e. 3 –6, – ( – 6 – 3), 4 + 1 i.e. – 3, 9, 5 respectively.
Co-factors of the elements of second row of | A | are
i.e. – (– 12 – 14), – 9 – 7, – (6 – 4) i.e. 26, — 16, – 2 respectively.
Co-factors of the elements of third row of | A | are
i.e. 12 + 7, – (9 – 14), – 3 – 8 i.e. 19, 5 – 11 respectively.
i.e. 3 –6, – ( – 6 – 3), 4 + 1 i.e. – 3, 9, 5 respectively.
Co-factors of the elements of second row of | A | are
i.e. – (– 12 – 14), – 9 – 7, – (6 – 4) i.e. 26, — 16, – 2 respectively.
Co-factors of the elements of third row of | A | are
i.e. 12 + 7, – (9 – 14), – 3 – 8 i.e. 19, 5 – 11 respectively.
