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Continuity And Differentiability

Question
CBSEENMA12034915

Differentiate the following w.r.t.x: straight e to the power of sin square root of straight x end exponent

Solution
Let space space space space straight y equals straight e to the power of sin square root of straight x end exponent
therefore space dy over dx equals straight e to the power of sin square root of straight x end exponent. straight d over dx left parenthesis sin square root of straight x right parenthesis equals straight e to the power of sin square root of straight x end exponent. cos square root of straight x cross times fraction numerator 1 over denominator 2 square root of straight x end fraction equals fraction numerator straight e to the power of sin square root of straight x end exponent. cos square root of straight x over denominator 2 square root of straight x end fraction

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