+91-8076753736 support@wiredfaculty.com

A PHP Error was encountered

Severity: Notice

Message: Undefined variable: temp_qds

Filename: Questions_Page/Ncert_Question.php

Line Number: 320

Backtrace:

File: /home/wiredfa1/public_html/application/views/final/Questions_Page/Ncert_Question.php
Line: 320
Function: _error_handler

File: /home/wiredfa1/public_html/application/controllers/Home.php
Line: 235
Function: view

File: /home/wiredfa1/public_html/index.php
Line: 315
Function: require_once

Sponsor Area

Continuity And Differentiability

Question

Wired Faculty App

$Find space dy over dx where space square root of straight x plus square root of straight y equals 20$

Solution

Here space square root of straight x plus square root of straight y equals 20 Differntiating space both space sides space straight w. straight r. tx comma space we space get comma fraction numerator 1 over denominator 2 square root of straight x end fraction plus fraction numerator 1 over denominator 2 square root of straight y end fraction dy over dx equals 0 or space space space space space space space space space space space space space fraction numerator 1 over denominator 2 square root of straight y end fraction dy over dx equals negative fraction numerator 1 over denominator 2 square root of straight x end fraction therefore space space space space space space space space space space space space space space space space space space space space space space space space space dy over dx equals negative fraction numerator square root of straight x over denominator square root of straight y end fraction

Some More Questions From Continuity and Differentiability Chapter

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation