A PHP Error was encountered

Severity: Notice

Message: Undefined variable: temp_qds

Filename: Questions_Page/Ncert_Question.php

Line Number: 320

Backtrace:

File: /home/wiredfa1/public_html/application/views/final/Questions_Page/Ncert_Question.php
Line: 320
Function: _error_handler

File: /home/wiredfa1/public_html/application/controllers/Home.php
Line: 235
Function: view

File: /home/wiredfa1/public_html/index.php
Line: 315
Function: require_once

Sponsor Area

Continuity And Differentiability

Question
CBSEENMA12034768

Find space dy over dx space where space straight x equals fraction numerator straight a left parenthesis 1 minus straight t squared right parenthesis over denominator 1 minus straight t squared end fraction comma space straight y space equals fraction numerator 2 bt over denominator 1 minus straight t squared end fraction

Solution
Here space space straight x equals fraction numerator straight a left parenthesis 1 minus straight t squared right parenthesis over denominator 1 minus straight t squared end fraction equals straight a open square brackets fraction numerator 1 minus straight t squared over denominator 1 plus straight t squared end fraction close square brackets
dx over dt equals straight a open square brackets fraction numerator left parenthesis 1 plus straight t squared right parenthesis begin display style straight d over dt end style left parenthesis 1 minus straight t squared right parenthesis minus left parenthesis 1 minus straight t squared right parenthesis. begin display style straight d over dt end style left parenthesis 1 plus straight t squared right parenthesis over denominator left parenthesis 1 plus straight t squared right parenthesis squared end fraction close square brackets
space space space space space space space space equals straight a open square brackets fraction numerator left parenthesis 1 plus straight t squared right parenthesis left parenthesis negative 2 straight t right parenthesis minus left parenthesis 1 minus straight t squared right parenthesis left parenthesis 2 straight t right parenthesis over denominator left parenthesis 1 plus straight t squared right parenthesis squared end fraction close square brackets equals straight a open square brackets fraction numerator negative 2 straight t minus 2 straight t cubed minus 2 straight t plus 2 straight t cubed over denominator left parenthesis 1 plus straight t squared right parenthesis squared end fraction close square brackets
space space space space space space space space equals straight a open square brackets fraction numerator negative 4 straight t over denominator left parenthesis 1 plus straight t squared right parenthesis squared end fraction close square brackets
therefore dx over dt equals negative fraction numerator 4 at over denominator left parenthesis 1 plus straight t squared right parenthesis squared end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space... left parenthesis 1 right parenthesis
Also space straight y space equals fraction numerator 2 bt over denominator 1 minus straight t squared end fraction equals 2 straight b open square brackets fraction numerator straight t over denominator 1 plus straight t squared end fraction close square brackets
dy over dt equals 2 straight b open square brackets fraction numerator left parenthesis 1 plus straight t squared right parenthesis begin display style straight d over dt end style left parenthesis straight t right parenthesis minus straight t begin display style straight d over dt end style left parenthesis 1 plus straight t squared right parenthesis over denominator left parenthesis 1 plus straight t squared right parenthesis squared end fraction close square brackets equals 2 straight b open square brackets fraction numerator left parenthesis 1 plus straight t squared right parenthesis.1 minus straight t space.2 straight t over denominator left parenthesis 1 plus straight t squared right parenthesis squared end fraction close square brackets
therefore space dy over dt equals fraction numerator 2 straight b left parenthesis 1 minus straight t squared right parenthesis over denominator left parenthesis 1 plus straight t squared right parenthesis squared end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space... left parenthesis 2 right parenthesis
Now space dy over dx equals fraction numerator begin display style dy over dt end style over denominator begin display style dx over dt end style end fraction equals fraction numerator 2 straight b left parenthesis 1 minus straight t squared right parenthesis over denominator left parenthesis 1 plus straight t squared right parenthesis squared end fraction cross times fraction numerator left parenthesis 1 plus straight t squared right parenthesis squared over denominator negative 4 at end fraction equals negative fraction numerator straight b left parenthesis 1 minus straight t squared right parenthesis over denominator 2 at end fraction.

Some More Questions From Continuity and Differentiability Chapter